Wolframalpha inverse how to#

Anyways I managed to do the plot using another application. What I was looking for was just a solution to a seperable differential equation, which would give me a velocity-time graph until the terminal velocity is reached. In this context just strict the Domain/ Range to real numbers. I perhaps should have given some back ground info, my mistake. The result I am expecting does not extend to the imaginary numbers.

Wolframalpha inverse how to#

This does make 'Using Solve as part of a program' somewhat problematic and infact there are many past posts upon those seeking advice on how to do it for a given program however you can't rely on special cases, you should supply |x|<1 and check the answer is reasonable, unless knowing what to expect of course :) Many or all Mathematica functions are aware of special simplifications of trigonometric functions, many other don't need to be aware by careful design. you should also realize that in this kind of area Mathematica is continually making advances which, for the better, sometimes change the answer Mathematica gives. Many papers have been written to describe what a complex number 'imaginary' should represent in various situations, so that is somewhat of a contrivance and you do need to know (graph it?) what they are doing (what is being done in this specific case) when an Im is in the answer.Īs far as special cases mentioned above, it might be up to you to insure when your asking Mathematica 'to know these things' that the functions your using are aware of them somehow or do not need to be aware. However that's a special result, true if |x| 0 & -(/2) 1, b -> 1, c -> 1} ĭuring evaluation of In:= Sqrt ArcTanh]Ģ]], (Sqrt Re = 0 & - 0 & - > The graph i see is like this, and i would say it is not invertible in general, but that regions of it may beĪh yes arctan is invertible now i remember Is f() one to one? are your variables following the rules of inversion (you didnt say) ? which variable is taken as f(x)=y? Graph the solution using mathematica, upload the graph, so we can see it breaks no rules (quite plainly easily by view) and can be inverted

You havent told Mathematica anything about these mystery variable, and it is likely cautiously and probably correctly avoiding answers that would not be true in 'the general case' of what you gave it You have many variables maybe dependant or independant, and i don't see what the graph looks likeĪ typical inversion routine from Algebra needs dependant y and independant x as arguments to it, and it appears Mathematica asks for this and you didn't provide it, and that you didn't use mathematica but a 'guesser' however the guesser cannot convey the information to you that your input is problematic in many ways Without having graphed it myself i'll underline what sander saidįunctions that 'pass tests' are invertible, not all relations are invertible

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